GLOSSARY ENTRY (DERIVED FROM QUESTION BELOW) | ||||||
---|---|---|---|---|---|---|
|
13:13 Jul 31, 2006 |
German to Polish translations [PRO] Medical - Biology (-tech,-chem,micro-) | |||||||
---|---|---|---|---|---|---|---|
|
| ||||||
| Selected response from: Domi_NM Local time: 09:48 | ||||||
Grading comment
|
Summary of answers provided | ||||
---|---|---|---|---|
5 +1 | roztwor lugu sodowego o stezeniu 1 M (1 mol/dm3) |
|
Discussion entries: 1 | |
---|---|
roztwor lugu sodowego o stezeniu 1 M (1 mol/dm3) Explanation: Roztwór 1M zawiera 1 mol substancji w 1 litrze (1 mol/dm3). 1 mol NaOH to 40 g. Czyli w 1 litrze 1M roztworu NaOH znajduje się 40 g NaOH ; mailgate.supereva.com/pl/pl.sci.chemia/msg101969.html -lug sodowy: wodny roztwor wodorotlenku sodu (NaOH) |
| |
Grading comment
| ||
Login to enter a peer comment (or grade) |
Login or register (free and only takes a few minutes) to participate in this question.
You will also have access to many other tools and opportunities designed for those who have language-related jobs (or are passionate about them). Participation is free and the site has a strict confidentiality policy.